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I am encoding a string that will be passed in a URL (via GET). 我正在编码一个将在URL中传递的字符串（通过GET）。 But if I use escape , encodeURI or encodeURIComponent , & will be replaced with %26amp%3B , but I want it to be replaced with %26 . 但是如果我使用escape ， encodeURI或encodeURIComponent ， &将被替换为%26amp%3B ，但我希望它被替换为%26 。 What am I doing wrong? 我究竟做错了什么？

#1楼

参考：

#2楼

There is HTML and URI encodings. 有HTML和URI编码。 & is & while %26 is & in . 是& 而%26是& 。

So before URI encoding your string you might want to HTML decode and then URI encode it :) 所以在URI编码你的字符串之前，你可能想要HTML解码，然后对它进行URI编码:)

var div = document.createElement('div');div.innerHTML = '&AndOtherHTMLEncodedStuff';var htmlDecoded = div.firstChild.nodeValue;var urlEncoded = encodeURIComponent(htmlDecoded);

result %26AndOtherHTMLEncodedStuff 结果%26AndOtherHTMLEncodedStuff

Hope this saves you some time 希望这能为您节省一些时间

#3楼

If you did literally this: 如果你真的这样做：

encodeURIComponent('&')

Then the result is %26 , . 然后结果是%26 ， 。 Make sure the string you are encoding is just & and not & 确保您编码的字符串只是 &而不是& to begin with...otherwise it is encoding correctly, which is likely the case. 开始...否则它正确编码，这可能是这种情况。 If you need a different result for some reason, you can do a .replace(/&/g,'&') before the encoding. 如果由于某种原因需要不同的结果，可以在编码之前执行.replace(/&/g,'&') 。

#4楼

Without seeing your code, it's hard to answer other than a stab in the dark. 没有看到你的代码，除了在黑暗中刺伤之外，很难回答。 I would guess that the string you're passing to encodeURIComponent() , which is the correct method to use, is coming from the result of accessing the innerHTML property. 我猜你正在传递给encodeURIComponent（）的字符串，这是正确使用的方法，来自访问innerHTML属性的结果。 The solution is to get the innerText / textContent property value instead: 解决方案是获取innerText / textContent属性值：

var str,     el = document.getElementById("myUrl");if ("textContent" in el)    str = encodeURIComponent(el.textContent);else    str = encodeURIComponent(el.innerText);

If that isn't the case, you can use the replace() method to replace the HTML entity: 如果不是这种情况，您可以使用replace（）方法替换HTML实体：

encodeURIComponent(str.replace(/&/g, "&"));

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